Template Function c4::operator!=(C const, basic_substring<C> const)

Function Documentation

Warning

doxygenfunction: Unable to resolve function “c4::operator!=” with arguments “(C const, basic_substring<C> const)”. Candidate function could not be parsed. Parsing error is Error when parsing function declaration. If the function has no return type: Error in declarator or parameters-and-qualifiers Invalid C++ declaration: Expecting “(” in parameters-and-qualifiers. [error at 39] template<class Alloc> C4_ALWAYS_INLINE bool operator!= (c4::csubstr ss, std::vector< char, Alloc > const &s) —————————————^ If the function has a return type: Error in declarator or parameters-and-qualifiers If pointer to member declarator: Invalid C++ declaration: Expected identifier in nested name, got keyword: bool [error at 43] template<class Alloc> C4_ALWAYS_INLINE bool operator!= (c4::csubstr ss, std::vector< char, Alloc > const &s) ——————————————-^ If declarator-id: Invalid C++ declaration: Expected identifier in nested name, got keyword: bool [error at 43] template<class Alloc> C4_ALWAYS_INLINE bool operator!= (c4::csubstr ss, std::vector< char, Alloc > const &s) ——————————————-^