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grpc
src
python
grpcio_tests
tests
bazel_namespace_package_hack.py
Go to the documentation of this file.
1
# Copyright 2019 The gRPC Authors
2
#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
10
# distributed under the License is distributed on an "AS IS" BASIS,
11
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
12
# See the License for the specific language governing permissions and
13
# limitations under the License.
14
15
import
os
16
import
site
17
import
sys
18
19
_GRPC_BAZEL_RUNTIME_ENV =
"GRPC_BAZEL_RUNTIME"
20
21
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# TODO(https://github.com/bazelbuild/bazel/issues/6844) Bazel failed to
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# interpret namespace packages correctly. This monkey patch will force the
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# Python process to parse the .pth file in the sys.path to resolve namespace
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# package in the right place.
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# Analysis in depth: https://github.com/bazelbuild/rules_python/issues/55
27
def
sys_path_to_site_dir_hack
():
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"""Add valid sys.path item to site directory to parse the .pth files."""
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# Only run within our Bazel environment
30
if
not
os.environ.get(_GRPC_BAZEL_RUNTIME_ENV):
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return
32
items = []
33
for
item
in
sys.path:
34
if
os.path.exists(item):
35
# The only difference between sys.path and site-directory is
36
# whether the .pth file will be parsed or not. A site-directory
37
# will always exist in sys.path, but not another way around.
38
items.append(item)
39
for
item
in
items:
40
site.addsitedir(item)
tests.bazel_namespace_package_hack.sys_path_to_site_dir_hack
def sys_path_to_site_dir_hack()
Definition:
bazel_namespace_package_hack.py:27
grpc
Author(s):
autogenerated on Thu Mar 13 2025 02:58:36